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Prime factors, exponent form and a factor tree.
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Prime factorisation
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From the sum of its proper divisors
Every integer above 1 has exactly one prime factorisation, ignoring order — the fundamental theorem of arithmetic. The number of divisors follows from it: add one to each exponent and multiply. Only primes up to the square root need testing, because any larger factor already has a smaller partner.
The Prime Factorization Calculator breaks a number into the primes that multiply to make it, shown as a product and in exponent form, with a factor tree drawn out and the complete list of divisors generated from the factorisation.
Decompose a number into the primes that multiply to make it, shown both as a plain product and in exponent form. A factor tree is drawn out, and the complete list of divisors is generated from the factorisation.
Every integer greater than one has exactly one prime factorisation, ignoring the order of the factors — this is the fundamental theorem of arithmetic, and it is why primes are described as the building blocks of the integers. The factorisation also answers questions that look unrelated: the number of divisors is found by adding one to each exponent and multiplying, and greatest common divisors and least common multiples both fall straight out of comparing two factorisations.
Each division step is shown, which is usually exactly what a homework question asks you to produce.
360 shown as 2³ × 3² × 5 rather than a long repeated product.
The full divisor list, its count and its sum, all derived from the factorisation rather than by brute force.
If the number is itself prime, the tool says so instead of returning a one-item list without comment.
Only primes up to the square root are tested, so large numbers factor quickly.
Anything from 2 upwards. Large values are handled with trial division up to the square root.
As a product of primes and in exponent form.
Each division step is shown, which is usually what homework asks you to draw.
Every divisor is generated, along with how many there are and their sum.
Writing a number as a product of prime numbers. 360 factorises to 2³ × 3² × 5, and by the fundamental theorem of arithmetic that decomposition is unique.
Divide by the smallest prime that goes in exactly, then repeat on the quotient. You only need to test primes up to the square root, because a larger factor would already have a smaller partner.
Add one to each exponent in the prime factorisation and multiply the results. For 360 = 2³ × 3² × 5¹ that gives 4 × 3 × 2 = 24 divisors.
No. Primes have exactly two distinct divisors, and 1 has only one. Excluding it is also what keeps prime factorisation unique.
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